16(t^2-1t-12)=0

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Solution for 16(t^2-1t-12)=0 equation:


Simplifying
16(t2 + -1t + -12) = 0

Reorder the terms:
16(-12 + -1t + t2) = 0
(-12 * 16 + -1t * 16 + t2 * 16) = 0
(-192 + -16t + 16t2) = 0

Solving
-192 + -16t + 16t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '16'.
16(-12 + -1t + t2) = 0

Factor a trinomial.
16((-3 + -1t)(4 + -1t)) = 0

Ignore the factor 16.

Subproblem 1

Set the factor '(-3 + -1t)' equal to zero and attempt to solve: Simplifying -3 + -1t = 0 Solving -3 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1t = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1t = 0 + 3 -1t = 0 + 3 Combine like terms: 0 + 3 = 3 -1t = 3 Divide each side by '-1'. t = -3 Simplifying t = -3

Subproblem 2

Set the factor '(4 + -1t)' equal to zero and attempt to solve: Simplifying 4 + -1t = 0 Solving 4 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1t = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1t = 0 + -4 -1t = 0 + -4 Combine like terms: 0 + -4 = -4 -1t = -4 Divide each side by '-1'. t = 4 Simplifying t = 4

Solution

t = {-3, 4}

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